#include<stdio.h> #include<math.h> void main() { int n,sum,r,digits; for(n=1;n<=1000;n++)  { digits=0; r=n; sum=0; while(r!=0) //Counting Digits { digits++; r/=10; } r=n; while(r!=0) /*Adding Digits Raised To a Power That Is Equal To Number of Digits * { sum+=pow((r%10),digits); r=r/10; } if(sum==n) { printf("%5d",sum); }
}
}
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Program to Display All Armstrong Numbers upto 1000
This post is for C program to display all Armstrong numbers less than 1000. But before all, I should tell what an Armstrong number is. An Armstrong number is a number that is the sum of its own digits each raised to the power of the number of digits. Consider an example. 153 is an Armstrong number. Since it is a 3 digit number, to check whether it is an Armstrong number or not, we should add the 3rd power digits together. So, in the program, we should have a code to determine number of digits in number, then add the nth powers (where n is the number of digits) of each digit in the number and check whether both the sum and original number are the same.
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